Three urns, called A, B, and C, are placed on a table. A certain number of marbles are placed in each urn.?

Let V0 = [n1]


[n2]


[n3]


be the 3X1 matrix that indicates the number of marbles in each urn. That is, there are n1 marbles in urn A, n2 marbles in urn B, and n3 marbles in urn C. An operation of shifting marbles from urn to urn is performed. In each stage of this operation, three things are done:


(i) 3/5 of the marbles in A are left in A, 1/5 of the marbles in A are moved to B, and 1/5 of the marbles in A are moved to C.


(ii) At the same time, ¼ of the marbles in B are moved to A, ½ of the marbles in B are left in B, and ¼ of the marbles in B are moved to C.


(iii) Simultaneously, 1/5 of the marbles in C are moved to A, 1/5 of the marbles in C are moved to B, and 3/5 of the marbles in C are left in C.





(c) Suppose that n1 = 20, n2 = 80, and n3 = 40. Calculate V5, the number of marbles in each urn after five stages of the operation have been performed.

Three urns, called A, B, and C, are placed on a table. A certain number of marbles are placed in each urn.?
v0 = [20 , 80 , 40]





v1 = [12+20+8 ,4+40+8 ,4+20+24]


= [40 , 52 , 48] ... the problem here is that the third urn has marbles which cannot be divided by 5.





v2 =[24+13+9 , 8+26+9 , 8+13+30]


= [46 , 43 , 51]


... i guess by this time... simply approximate the number of marbles to be allocated...








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Reply:is this the math book from Congress -


used for balancing the budget ?

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