Sunday, August 2, 2009

A 2 µC charge with mass 0.1 kg accelerates at 2 m/s^2 in a uniform electric field. The magnitude of the field

is most nearly...?


a. 10^5 N/C


b. 10^-5 N/C


c. 2 N/C


d. 0.2 N/C


e. 0.1 N/C





I need to show work. Please help!

A 2 µC charge with mass 0.1 kg accelerates at 2 m/s^2 in a uniform electric field. The magnitude of the field
The formula for acceleration in an electric field is a = q*E / m, where q is the charge, E is the electric field, and m is the mass. If you want to know the electric field, use E = a*m / q or E = F / q since a*m is force.





E = (2 m/s^2 x 0.1 kg) / (2 x 10^-6 C) = 0.2 N / 2 x 10^-6 C





= 100,000 N/C or 1 x 10^5 N/C





Therefore the answer is a. Glad I could help.


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