Friday, July 31, 2009

Show that p(B|C)=p(B|~C)?

hey, can anyone help me to answer that question?


given that: P(A|B)%26lt;P(A|~B)


P(A|B,C)%26gt;P(A|~B,C)


P(A|B,~C)%26gt;P(A|~B,~C)


where ~B mean 'not B'





Question: show that if p(B|C)=p(B|~C), then not all of the above three inequalities can occur simultaneously





thanks so much

Show that p(B|C)=p(B|~C)?
rashers .


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